-4.9t^2+30.5t+8.3=0

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Solution for -4.9t^2+30.5t+8.3=0 equation: 



-4.9t^2+30.5t+8.3=0

a = -4.9; b = 30.5; c = +8.3;
Δ = b2-4ac
Δ = 30.52-4·(-4.9)·8.3
Δ = 1092.93
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30.5)-\sqrt{1092.93}}{2*-4.9}=\frac{-30.5-\sqrt{1092.93}}{-9.8}
$


$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30.5)+\sqrt{1092.93}}{2*-4.9}=\frac{-30.5+\sqrt{1092.93}}{-9.8}
$

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